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04-08-2016
Mathematics

contestada

Solve the equation below:
Let f and g be differentiable functions such that
f(1) = 4, g(1) = 3, f'(3) = -5, f'(1) = -4, g'(1) = -3, g'(3) = 2
If H(x) = f(g(x)), then h'(1) =

Respuesta :

08-08-2016

Remember the chain rule.
L(x)=f(g(x))

L'(x)=f'(g(x))g'(x)

take the derivative of f(g(x)). just treat them like they are variables. so you get:

h'=f'(g(x))g'(x)

now plug in your x value and evaluate:

h'(1)=f'(g(1))(g'(1))

substitute in values that you know and evaluate again
h'(1)=f'(3)(-3)

h'(1)=(-5)(-3)=15

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