taylorbonham251 taylorbonham251

03-12-2014
Mathematics

contestada

how do you solve polynomial equation by factoring
2x^3 - 12x^2 = 32x - 192

Respuesta :

konrad509 konrad509

03-12-2014

[tex]2x^3 - 12x^2 = 32x - 192\\ 2x^3-12x^2-32x+192=0\\ 2(x^3-6x^2-16x+96)=0\\ 2(x^2(x-6)-16(x-6))=0\\ 2(x^2-16)(x-6)=0\\ 2(x-4)(x+4)(x-6)=0\\ x=4 \vee x=-4 \vee x=6[/tex]

Answer Link

Otras preguntas

after 3198 hours, how much if a 0.840 g sample of radium remains

Rewrite the equation so that it does not have fractions 4 + 2/3x = 3/4 do not use decimals

Hi I need a lot of help

U.S. Groups of the Late 1700s and Early 1800s Women Children Indentured Servants Native Americans African Americans Working Class Why did all of the groups list

Where does the minute hand point at ten past seven

Solve for x: 81 ^-2 : 729 ^1-X = 9 ^2x

Factor completely. X^3 – 8x^2- 2x+ 16 =

Discussion Questions Directions: Brainstorm your answers to the following questions in the space provided. Be prepared to share your original ideas in a class d

Section-II V. Answer any Three of the following questions. 33) What is contraception? Briefly explain two barrier methods and two surgical methods to prevent co

what is x please fast[tex]3 {x}^{2} - 5x + 4x = 3 {x}^{2} - 5 {x}^{2} + 9x[/tex]